What is the total resistance of the circuit shown?

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Prepare for the PMMI Industrial Electricity Test with quizzes featuring flashcards and multiple-choice questions. Each answer is explained with hints to ensure a thorough understanding. Gear up to excel in your exam!

Multiple Choice

What is the total resistance of the circuit shown?

Explanation:
Total resistance is found by simplifying the network using series and parallel rules. In this circuit, resistors are arranged so that a pair is in parallel, and that parallel combination sits in series with another resistor. You first find the parallel equivalent: if the two resistors are 10 Ω and 30 Ω, their parallel result is Rp where 1/Rp = 1/10 + 1/30 = 4/30, so Rp = 7.5 Ω. Then you add the resistor in series with that parallel group: 7.5 Ω + 7.5 Ω = 15 Ω. So the total resistance comes out to 15 Ω. The other numbers would come from using different combinations or misidentifying the series/parallel relationships.

Total resistance is found by simplifying the network using series and parallel rules. In this circuit, resistors are arranged so that a pair is in parallel, and that parallel combination sits in series with another resistor. You first find the parallel equivalent: if the two resistors are 10 Ω and 30 Ω, their parallel result is Rp where 1/Rp = 1/10 + 1/30 = 4/30, so Rp = 7.5 Ω. Then you add the resistor in series with that parallel group: 7.5 Ω + 7.5 Ω = 15 Ω. So the total resistance comes out to 15 Ω. The other numbers would come from using different combinations or misidentifying the series/parallel relationships.

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